WebIn figure, if ∠BAC =90° and AD⊥BC. Then, (a) BD.CD = BZC² (b) AB.AC = BC² (c) BD.CD=AD² (d) AB.AC =AD² Solution: c) BD.CD=AD² Explanation: From ∆ADB and ∆ADC, According to the question, we have, ∠D = ∠D = 90° (∵ AD ⊥ BC) ∠DBA = ∠DAC [each angle = 90°- ∠C] Using AAA similarity criteria, ∆ADB ∼ ∆ADC BD/AD = AD/CD BD.CD = AD 2 2. Web1. In figure, if ∠BAC =90° and AD⊥BC. Then, (a) BD.CD = BZC² (b) AB.AC = BC² (c) BD.CD=AD² (d) AB.AC =AD². Solution: c) BD.CD=AD². Explanation: From ∆ADB and ∆ADC, …
2. In the given figure, angle BAC = 90° and AD …
WebAug 18, 2024 · In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then, (A) BD . CD = BC 2 (B) AB . AC = BC 2 (C) BD . CD = AD 2 (D) AB . AC = AD 2 triangles ncert class-10 Please log in or … WebMar 7, 2024 · In the given figure, angle BAC = 90° and AD perpendicular BC. Then, A)BC.CD = BC² B)AB.AC =BC² C) BD.CD = AD² D)AB.AC = AD² Answer: Option C) BD.CD = AD² … new wapping street map
[SOLVED] In the figure given below , BAC = 90^0 and AD BC. then AD^2
WebMay 18, 2024 · In Fig., ∠BAC = 90° and AD ⊥ BC. The number of right triangles in the figure is (A) 1 (B) 2 (C) 3 (D) 4 geometry class-6 1 Answer +1 vote answered May 18, 2024 by Varun01 (53.6k points) selected May 22, 2024 by Subnam01 (C) 3 We have, ∠BAC = 90° and AD ⊥ BC ∵ ∠BDA = ∠CDA = ∠BAC = 90° ∴ There are 3 right triangles formed in the given … WebMay 18, 2024 · In Fig. 6.13, ∠BAC = 90°, AD ⊥ BC and ∠BAD = 50°, then ∠ACD is (a) 50° (b) 40° (c) 70° (d) 60° asked Aug 16, 2024 in Mathematics by AbhinavMehra ( 22.6k points) … WebGiven, ABC is an equilateral triangle with AD as altitude. We have to find the value of 4AD². We know that in an equilateral triangle all the sides are of equal length. Let AB = BC = AC = x units ----- (1) Let AD = h units ----- (2) In an equilateral triangle, the altitude AD bisects BC. So, BD = CD = BC/2 = x/2 mika catering scheyern