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In a fort 300 men had provisions for 90 days

WebMar 2, 2024 · First 90 days were there but at present days are left 90-20= 70 days There were 300 men but 50 men then left, Remaining one's= 300-50= 250 men So, provision for 300 men= 70 days Provision for 250 men will be = x As its indirect variation, so formula 70/x= 250/300 70×300/250= x 2100/25= x 420/5= x Hope my answer help you. My pleasure WebMar 8, 2014 · in a fort 300 men had provision for 90 days after 20 days,50 men left the fort how long would the food last,at the same rate - Maths - NCERT Solutions Board Paper …

A fort has provisions for 300 men for 90 days After 20 days, 50 men …

WebA fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate? A 88 days B 48 days C 84 days D 44 days Medium … WebA fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate? A 62 B 84 C 56 D 72 Easy Solution Verified by Toppr Correct option is B) Remaining number of men =(300−50)=250. Remaining number of … incoterm selbstabholung https://more-cycles.com

In a Fort, 300 soldiers had of food provision for 90 days. after 20 ...

WebSep 18, 2024 · Answer: 84 Days Step-by-step explanation: Remaining number of men = (300−50)=250. Remaining number of days = (90−20)days=70 days 300 men had provisions for 70 days 1 man had provisions for (300×70) days... [less men, more days] 250 men had provisions for 300×70/250 days =84 days... [more men, less days] WebA garrison of 500 men had provisions for 24 days. However, a reinforcement of 300 men arrived. The food will now last for (a) 18 days (b) 17 1 2 days (c) 16 days (d) 15 days. Q. In a garrision 500 men had provision for 60 days. A reinforcement of 500 men arrived. ... Q. A fort provisioned for 42 days, after 10 days, a reinforcement of 200 men ... WebApr 4, 2024 · It is given that 150 men had food for 45 days. After 10 days, 150 men still had food for 35 days. Since, 25 men left the fort so $150 - 25 = 125$ men are left in the fort. Now, let us suppose that 125 men had food for the x number of days. We know that we have the case of indirect proportion here because as the number of men will decrease food ... incoterm rules 2020

In a Fort, 300 soldiers had of food provision for 90 days. after 20 ...

Category:A garrison had provisions for 1500 men for 30 days. After some days …

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In a fort 300 men had provisions for 90 days

In a fort , 300 men had provisions for 90 days. After 20 days, ... Filo

WebMay 18, 2016 · A fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate. So men is inversely proportional to … WebSolution Verified by Toppr Correct option is C) Let there be x men originally. So, x men had provisions 40 days whereas (x+500) men consumed it in 35 days Let us find the number of men in the fort as shown below: xx+500= 3540 ⇒ xx+500= 78⇒7(x+500)=8x ⇒7x+3500=8x ⇒8x−7x=3500 ⇒x=3500 Hence, there are 3500 men in the fort. Was this answer helpful? 0 0

In a fort 300 men had provisions for 90 days

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WebA fort had provisions with 300 men for 90 days. After 20 days 50 men left the fort. How long would the food last at the same rate? Question: A fort had provisions with 300 men for 90 … WebJun 30, 2024 · 300 men x 90 days = 27000 man- days of provisions . 300 men x 20 days = 6000 man days of provisions leaving 21000 man days of provisions . 21000 m-d / 250m = …

WebGiven: In a Fort, 300 soldiers had of food provision for 90 days. After 20 days, 50 soldiers left the Fort, So, the remining soldiers 250 had the food for x days. As soldiers increases the … WebAug 2, 2016 · First 90 days were there but at present days are left 90-20= 70 days. There were 300 men but 50 men then left, Remaining one's= 300-50= 250 men. So, provision for …

WebAnswer (s) Ans 1= 120 Men - 195 days (provision left after 5 days) 30 men killed Men left - 90 Days - D so 120 x 195 = 90 x D D= 260 days Ans 2= 1200 soldiers - 24 days (after 4 days) soldiers leaving= S days= 32 so (1200-S) x 32 = 1200 x 24 S =300 soldiers By: Niharika, 1 decade ago 3 like this answer consider 1 person consumes "X" food per day WebA fort had provisions for 300 men for 90 days. After 20 days, 50 men left the fort. How long would the food last at the same rate? Class:8 PhipsArt Almost yours: 2 weeks, on us...

WebMar 9, 2014 · A fort has provisions for 300 men for 90 days.After 20 days, 50 men left the the fort then how long would the provisions last at the same rate?

WebJan 13, 2024 · A fort has provisions for 300 men for 90 days . After 20 days , 50 men left the fort . How long would the food last at the same rate ? Advertisement Answer 3 people found it helpful tanunagar21 Answer: 84 Step-by-step explanation: Remaining number of men = (300−50)=250. Remaining number of days = (90−20)days=70 days incoterm stadWebA man can do a work in 3 days alone and a women can do the same work in 9 days alone. If both are work together in how many days they finished the same work. There are 8 mango … incoterm selbstabholerWebFeb 22, 2024 · Solution For In a fort , 300 men had provisions for 90 days. After 20 days, 50 men left the fort. How long would the provisions last at the same rate? incoterm shipwayWebNov 2, 2024 · In a fort, there are 1500 soldiers and they have provisions for 90 days.If 600 soldiers leave the fort and the remaining soldiers increase their consu askedNov 2, 2024in Mathematicsby Dhruvan(88.7kpoints) class-8 time-and-work-pipes-and-cisterns 0votes 1answer In a garrison of 10 soldiers, there was enough food to last for 28 days. incoterm stands forWebRight Answer is: SOLUTION First statement says that 300 men has 90 days food so total is 300*90=2700 After 20 days 50 men left that is 250 men still there and 70 days food of … incoterm rsWeb60 days. Send all 160 soldiers out food foraging- 40 at a time- 20 forage for food while the others stand guard 3 to four hours, then they switch places. I would assume the garrison is near a fresh water resource ( lake, stream or river, and/or near the ocean. Assume two groups go out daily. incoterm spacer e100incoterm site